42. | If the product 4864 x 9 P 2 is divisible by 12, then the value of P is: | |||||||||
Answer: Option E Explanation:
Clearly, 4864 is divisible by 4. So, 9P2 must be divisible by 3. So, (9 + P + 2) must be divisible by 3. P = 1. |
43. | Which one of the following is the common factor of (4743 + 4343) and (4747 + 4347) ? | |||||||
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44. | -84 x 29 + 365 = ? | |||||||||||||||||
Answer: Option D Explanation:
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45. | A number when divided by 296 leaves 75 as remainder. When the same number is divided by 37, the remainder will be: | |||||||
Answer: Option A Explanation:
Let x = 296q + 75 = (37 x 8q + 37 x 2) + 1 = 37 (8q + 2) + 1 Thus, when the number is divided by 37, the remainder is 1. |
46. | In dividing a number by 585, a student employed the method of short division. He divided the number successively by 5, 9 and 13 (factors 585) and got the remainders 4, 8, 12 respectively. If he had divided the number by 585, the remainder would have been | |||||||
Answer: Option D Explanation:
5 | x z = 13 x 1 + 12 = 25 -------------- 9 | y - 4 y = 9 x z + 8 = 9 x 25 + 8 = 233 -------------- 13| z - 8 x = 5 x y + 4 = 5 x 233 + 4 = 1169 -------------- | 1 -12 585) 1169 (1 585 --- 584 --- Therefore, on dividing the number by 585, remainder = 584. |
47. | In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, what is the dividend ? | |||||||||||||
Answer: Option D Explanation:
Divisor = (5 x 46) = 230
Dividend = (Divisor x Quotient) + Remainder = (230 x 23) + 46 = 5290 + 46 = 5336. |
48. | 4500 x ? = 3375 | |||||||||||||||||||||||
Answer: Option B Explanation:
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49. | What smallest number should be added to 4456 so that the sum is completely divisible by 6 ? | |||||||||
Answer: Option C Explanation:
6) 4456 (742 42 --- 25 24 Therefore, Required number = (6 - 4) = 2. --- 16 12 --- 4 |
50. | What least number must be subtracted from 13601, so that the remainder is divisible by 87 ? | |||||||||
Answer: Option C Explanation:
87) 13601 (156 87 ---- 490 435 ---- 551 522 --- 29 --- Therefore, the required number = 29. |