52. | If the number 97215 * 6 is completely divisible by 11, then the smallest whole number in place of * will be: | |||||||||
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53. | (112 + 122 + 132 + … + 202) = ? | ||||||||||||||||||||||
Answer: Option B Explanation:
(112 + 122 + 132 + … + 202) = (12 + 22 + 32 + … + 202) – (12 + 22 + 32 + … + 102)
= (2870 – 385) = 2485. |
54. | If the number 5 * 2 is divisible by 6, then * = ? | |||||||
Answer: Option A Explanation:
6 = 3 x 2. Clearly, 5 * 2 is divisible by 2. Replace * by x. Then, (5 + x + 2) must be divisible by 3. So, x = 2. |
55. | Which of the following numbers will completely divide (4915 – 1) ? | |||||||
Answer: Option A Explanation:
(xn – 1) will be divisibly by (x + 1) only when n is even. (4915 – 1) = {(72)15 – 1} = (730 – 1), which is divisible by (7 +1), i.e., 8. |
56. |
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Answer: Option D Explanation:
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57. |
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58. | On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is: | |||||||
Answer: Option A Explanation:
Clearly, (2272 – 875) = 1397, is exactly divisible by N. Now, 1397 = 11 x 127 The required 3-digit number is 127, the sum of whose digits is 10. |
59. | A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 9 are wrong and the other digits are correct, then the correct answer would be: | |||||||
Answer: Option C Explanation:
987 = 3 x 7 x 47 So, the required number must be divisible by each one of 3, 7, 47 553681 (Sum of digits = 28, not divisible by 3) 555181 (Sum of digits = 25, not divisible by 3) 555681 is divisible by 3, 7, 47. |
60. | How many prime numbers are less than 50 ? | |||||||
Answer: Option B Explanation:
Prime numbers less than 50 are: Their number is 15 |