Study the following table and answer the questions based on it.
Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
Year Item of Expenditure
Salary Fuel and Transport Bonus Interest on Loans Taxes
1998 288 98 3.00 23.4 83
1999 342 112 2.52 32.5 108
2000 324 101 3.84 41.6 74
2001 336 133 3.68 36.4 88
2002 420 142 3.96 49.4 98
1.
What is the average amount of interest per year which the company had to pay during this period?
A. Rs. 32.43 lakhs B. Rs. 33.72 lakhs
C. Rs. 34.18 lakhs D. Rs. 36.66 lakhs
Answer & Explanation
Answer: Option D
Explanation:
Average amount of interest paid by the Company during the given period
= Rs. [ 23.4 + 32.5 + 41.6 + 36.4 + 49.4 ] lakhs
5
= Rs. [ 183.3 ] lakhs
5
= Rs. 36.66 lakhs.
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2.
The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?
A. 0.1% B. 0.5%
C. 1% D. 1.25%
Answer & Explanation
Answer: Option C
Explanation:
Required percentage
= [ (3.00 + 2.52 + 3.84 + 3.68 + 3.96) x 100 ] %
(288 + 342 + 324 + 336 + 420)
= [ 17 x 100 ] %
1710
~= 1%.
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3.
Total expenditure on all these items in 1998 was approximately what percent of the total expenditure in 2002?
A. 62% B. 66%
C. 69% D. 71%
Answer & Explanation
Answer: Option C
Explanation:
Required percentage
= [ (288 + 98 + 3.00 + 23.4 + 83) x 100 ] %
(420 + 142 + 3.96 + 49.4 + 98)
= [ 495.4 x 100 ] %
713.36
~= 69.45%.
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4.
The total expenditure of the company over these items during the year 2000 is?
A. Rs. 544.44 lakhs B. Rs. 501.11 lakhs
C. Rs. 446.46 lakhs D. Rs. 478.87 lakhs
Answer & Explanation
Answer: Option A
Explanation:
Total expenditure of the Company during 2000
= Rs. (324 + 101 + 3.84 + 41.6 + 74) lakhs
= Rs. 544.44 lakhs.
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5.
The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately?
A. 4:7 B. 10:13
C. 15:18 D. 5:8
Answer & Explanation
Answer: Option B
Explanation:
Required ratio
= [ (83 + 108 + 74 + 88 + 98) ]
(98 + 112 + 101 + 133 + 142)
= [ 451 ]
586
= 1
1.3
= 10 .
13