SQL Star Written Test Pattern

SQL Star Written Test Pattern and selection Procedure

Time Limit : 90 Minutes

Max Marks :75

Technical and aptitude tests

Technical Interview

HR Interview

SQL STAR PAPER ON 10TH OCTOBER 

Duration: 90 Mins

Max.Marks: 75

Directions:  Study the following mathematical problems. Encircle the right answer.

PART – II
Technical-C

1.If   a b c is input, then the following program results

char x,y,z;

printf(“%d”,scanf(“%c %c %c “,&x,&y,&z));

3.Find the output

int a=4,b=6;

printf(“%d”,a= =b);

a) error message           b)0       c)1       d)none

4.Find output

while(printf(“%d”, printf(“az”)))

printf(“by”);

a) azbybyby…..                                    b) azbyazbyazbyaazby…..
c) syntax error                                      d) none

5.Find the output

main()

{

inc(); inc(); inc(); }

inc() { static int x;

printf(“%d”,++x);

}

a) prints 012               b) prints 123     c) prints 3 consecutive but unpredictable numbers    d) prints 111

6.What will be the output of the following?

main()

{

int k=35;

printf(“\n %d %d”, k>40);

}

7.           main()

{

int ivar, *iptr;

ivar=5;

iptr=&ivar;

pritnf(“%d \n”,ivar);

*iptr=*iptr+1;

printf(“%d \n”,ivar);

}

what is the output

a)5 1      b) 5 0         c) 5 6        d) 5 5

8.What is the output of the program ?

void main()

{

static int I = 5;

printf(“ I = %d “,i–);

if(i) main();

}

9.What is the output of the program?

void main()

{

char *p = “%d\n”:

int I =5;

printf(p,I);

}

10        #include

int a=45;

#define a 10

main()

{

Printf(“%d”,a);

}

11.Predicts error in followings

display(char *);

main()

{

Char string[ ]=”Hello World”;

}

Void display(char *string)

{

Printf(“%s”, string)

}

12.       #define C -2

Main()

{

C=89;

Printf(“c=%d”,c);

}

13.       main()

{

Enum {A,B=1,C);

B=45;

Printf(“%d\n”,B);

}

14.With every use of a memory allocation function, what function should be used to release allocated memory which is no longer needed?

15.       char* myfunc (char *ptr)

{

Ptr+=3;

Return (ptr);

}

Int main()

{

Char *x, *y;

X=”HELLO”;

Y=myfunc(x);

Printf(“y=%s\n”,y);

Return 0;

}

16.       int x[]=(1,4,8,5,1,4);

int  *ptr,y;

ptr= x+4;

y = ptr – x;

17.What is the output of the following program ?

#include

#include

main() {
typedef union {
int a;a
char b[10];
float c;
}
Union;

Union x,y = {100};
x.a = 50;
strcpy(x.b,”hello”);
x.c = 21.50;
printf(“Union x : %d %s %f n”,x.a,x.b,x.c);
printf(“Union y : %d %s %f n”,y.a,y.b,y.c);
}

18. What is the output of this Program ?

main()
{
char *p1=“name”;
char *p2;
p2=(char*)malloc(20);
memset (p2, 0, 20);
while(*p2++ = *p1++);
printf(“%s\n”,p2);
}

19.       main()

{
int x=20,y=35;
x=y++ + x++;
y= ++y + ++x;
printf(“%d%d\n”,x,y);
}

20.       #define swap(a,b) a=a+b;b=a-b;a=a-b;
void main()
{
int x=5, y=10;
swap (x,y);
printf(“%d %d\n”,x,y);
swap2(x,y);
printf(“%d %d\n”,x,y);

}

int swap2(int a, int b)
{
int temp;
temp=a;
b=a;
a=temp;
return 0;
}

a)10, 5

b) 5,10

c) compilation Error

d) No output
21.       Predict the output or error(s) for the following:

#include
main()
{
struct xx
{
int x=3;
char name[]=”hello”;
};
struct xx *s;
printf(“%d”,s->x);
printf(“%s”,s->name);
}

22.       Analyze the output

#include

main()
{
char s[]={‘a’,’b’,’c’,’\n’,’c’,”};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf(“%d”,++*p + ++*str1-32);
}

23.       #include

main()
{
int a[2][2][2] = { {10,2,3,4}, {5,6,7,8}  };
int *p,*q;
p=&a[2][2][2];
*q=***a;
printf(“%d—-%d”,*p,*q);
}

24.       main()

{
char *p=”hai friends”,*p1;
p1=p;
while(*p!=”) ++*p++;
printf(“%s   %s”,p,p1);
}

25.       main()

{
static char names[5][20]={“pascal”,”ada”,”cobol”,”fortran”,”perl”};
int i;
char *t;
t=names[3];
names[3]=names[4];
names[4]=t;
for (i=0;i<=4;i++)
printf(“%s”,names[i]);
}

26.       void main()

{
int  const * p=5;
printf(“%d”,++(*p));
}

27.       #include

#define clrscr() 100
main()
{
clrscr();
printf(“%d\n”,clrscr());
}

28.       Predict the output or error(s) for the following:

#include

main()

{

int i,j;
for(i=0;i<=10;i++)
{
j+=5;
assert(i<5);
}

29.       main()
{
int i=-1;
+i;
printf(“i = %d, +i = %d \n”,i,+i);
}

30.       main()
{
char *cptr,c;
void *vptr,v;
c=10;  v=0;
cptr=&c; vptr=&v;
printf(“%c%v”,c,v);
}

Technical-Operating System

5 .  _________________ is a memory _management  scheme that permits the physical address space of a process to be noncontiguous.

6.  ______________ is a lightweight process.

8.  _____________ keeps track of a proceses creation tine as well as the cpu time that it consumes during its lifetime

9.  ______________– required to complete a critical task within a guaranteed amount of time

10.   In polling mode the kernel checks each I/O device if it generated an interrupt or not. True/False?