ICICI bank sample question and answers, Bank based Data intrepreatation data sufficiency questions with answers,ICICI bank Probationary officer practice question papers
1. A Company ABC Limited arrange a training programme for its employees from its Marketing Finance and HRD Department. Each participant is awarded a grade at the end of the training programme. The total number of employees of the Finance Department participating in the programme is twice the number of candidates of HRD Department who have secured ‘Above Average’ grade. The total number of candidates who have obtained ‘Average’ grade, is six times the number of candidates of the Marketing who have obtained ‘Excellent’ grade and the number of candidates of the HRD Department with ‘Above Average grade is 1/3rd the total number of candidates of the HRD Department. Your superior has given you an incomplete chart to be completed.
GRADES | Total | ||||
Class | Excellent | Very Good | Above Average | Average | |
Marketing | 6 | 32 | |||
HRD | 2 | 5 | 48 | ||
Finance | 7 | ||||
Total | 13 | 31 | 137 |
1. I. The number of employees of the Finance Department getting ‘Above Average ‘grade is
a) 13
b) 11
c) 9
d) 7
e) None of these
1. II. The least number of employees getting ‘Average’ grade, are from
a) Marketing Department
b) Finance Department
c) HRD Department
d) HRD and Finance Department
e) None of these
1. III. The number of employees of the HRD Department getting ‘Average’ grade from what per cent of the total number of employees participating in the programme ?
a) 29.93%
b) 11.68%
c) 35.04 %
d) 18.25%
e) None of the these
1. IV. The training programme was conducted by Perfect trainers Private Limited. It charged Rs.4500/- per employee towards the cost of training. If it offered a discount of 7.5% to those candidates who secured ‘Average’ grade, then, what is the total fee payable by company ABC Limited to Perfect Trainers Private Limited, to the nearest thousand ?
a) Rs.455000/-
b) Rs.604000/-
c) Rs.507000/-
d) Rs.537000/-
e) None of these
2. The graph shows the Exports and Imports in 1999 of country ‘X’ in $ million for the period March 2009 to September 2009.
2. I. What is the average value of imports between March and September, 2009 ?
a) 2810.6
b) 3150.9
c) 2980.8
d) 3150.3
e) None of these
2. II. What is the average value of Exports between April and August, 2009 ?
a) 2694.3
b) 3106.8
c) 2695.6
d) 3107.4
e) None of these
2. III. What is the percentage increase in imports between April and May, 2009 ?
a) 5.80
b) 6.30
c) 8.04
d) 7.60
e) None of these
2. IV. The change in Trade GAP [import as a percentage of Export] between July and August, 2009, was approximately :-
a) Increase 3.55 per cent
b) Decrease 3.55 per cent
c) Increase 2.87 per cent
d) Decrease 2.34 per cent
e) None of these
2. V. What is the difference in exports between the periods March to May and June to August (in $ million) ?
a) 418
b) 592
c) 579
d) 585
e) None of these
2. VI. If the exports during March, 2009 is approximately 24.32 % more than that during February, 2002, then, what was the approximate during February, 2009 (in $ million) ?
a) 2658
b) 2562
c) 2652
d) 2656
e) None of these
2. VII. What is the Trade Balance for September, 2009 ?
a) 159
b) -159
c) -178
d) Data Insufficient
e) None of these
3. An unbiased die is tossed 60 times
THE SCORE AND CORRESPONDING FREQUENCY IN THE CASE OF A DIE TOSSED 60 TIMES
The frequency distribution showing the ‘expected’ outcomes against the score will appear as in :-
a) Figure (I)
b) Figure (II)
c) Figure (III)
d) Figure (IV)
e) Figure (V)
4.
4. I. In How many of the given years were the imports of company P more than its exports ?
a) 7
b) 4
c) 3
d) 5
e) None of these
4. II. In how many of the given years were the exports of company Q more than its imports ?
a) 3
b) 2
c) 5
d) 1
e) None of these
4. III. If the exports of company P in 2003 and 2004 taken together were Rs.72 crore, then, what were the imports of the company for the two years, taken together ?
a) 80 crore
b) 65 crore
c) 57.6 crore
d) 90 crore
e) None of these
4. IV. The exports of company Q with relation to imports were maximum in which year ?
a) 2006
b) 2008
c) 2003
d) 2005
e) Cannot be determined
4. V. If the exports of Company Q in the year 2007 were Rs.77 crore, then, what were the imports of the company in that year ?
a) 86 crore
b) 107.5 crore
c) 103.95 crore
d) 101 crore
e) None of these
4. VI. If Export of company P in 2006
+ Export of company Q in 2002 = 96 crore
then Import of company P in 2006
+ Import of company Q in 2002 = ?
a) 86.4 crore
b) 96.4 crore
c) 89.5 crore
d) 98.7 crore
e) None of these
5. A student scored a total of 440 marks out of 600 in a certain examination. Look at the Pie Diagram and answer the following questions :-
MARKS SCORED BY A STUDENT IN VARIOUS SUBJECTS
5. 1. The marks scored in French, Hindi, English and Social Studies, when added together, represent what percentage of the total marks obtained ?
a) 63.15
b) 52.62
c) 58.64
d) 56.39
e) None of these
5. II. The marks scored in Science and Mathematics, added together, exceed the marks scored in French and Social Studies, added together by how many marks ?
a) 54
b) 46
c) 40
d) 51
e) None of these
5. III. The difference of marks between Hindi and English is the same as that between
a) Social Studies and Maths
b) Science and Maths
c) French and Hindi
d) Science and Social Studies
e) None of these
5.IV. The subject in which the student scored 67 marks is ——————–
a) English
b) French
c) Science
d) Social Studies
e) Hindi
6. The graph shows the production of finished steel, sector wise, for the years 2002-2009.
THE PRODUCTION OF FINISHED STEEL SECTOR-WISE, FOR THE YEARS 2002-2009
6.I. Production in the private sector for 2007-08 is what per cent of the total production of 2007-08 ?
a) 37.54
b) 62.46
c) 24.91
d) 52.46
e) None of these
6.II. During which year was the percentage increase in total production highest as compared to the previous year ?
a) 2005-06
b) 2007-08
c) 2006-07
d) 2003-04
e) None of these
6.III. During which year was the percentage increase in total production lowest as compared to the previous year ?
a) 2003-04
b) 2005-06
c) 2007-08
d) 2004-05
e) None of these
6.IV. The percentage increase in production for the private sector from 2002-03 to 2007-08 is
a) 48.13
b) 92.80
c) 31.69
d) 86.73
e) None of these
6.V. What is the percentage share of the public sector in the total production for the year 2008-09 ?
a) 37.85
b) 62.46
c) 24.91
d) 32.54
e) None of these
7. EXPORTS IMPORTS AND TRADE BALANCE (Rs.CRORE)
Sr. No. | Year | Imports | Exports | Balance of Trade |
1. | 1998-1999 | 22244 | 15674 | – 6570 |
2. | 1999-2000 | 28235 | 20232 | – 8003 |
3. | 2000-2001 | 35416 | 27681 | – 7735 |
4. | 2001-2002 | 43193 | 32553 | – 10640 |
5. | 2002-2003 | 47851 | 44042 | – 3809 |
6. | 2003-2004 | 63375 | 53688 | – 9687 |
7. | 2004-2005 | 73101 | 69749 | – 3352 |
8. | 2005-2006 | 89970 | 82673 | – 7297 |
9. | 2006-2007 | 122678 | 106353 | – 16325 |
10. | 2007-2008 | 136844 | 117524 | – 19320 |
7.I. Which of the following shows an increase every year ?
a) Exports
b) Imports
c) Balance of Trade
d) All the three
e) None of these
7.II. The ratio of Imports to Exports was maximum during which of the following years ?
a) 2001-02
b) 2000-01
c) 1998-99
d) 2003-04
e) None of these
7.III. What was the maximum annual percentage increase in Exports, over the years ?
a) 35.29
b) 36.04
c) 36.82
d) 36.43
e) None of these
7.IV. What was the minimum annual percentage increase in Imports, over the years ?
a) 10.78
b) 10.94
c) 11.55
d) 9.87
e) None of these
7.V. What was the total Trade Deficit from 2000-01 to 2005-06 ?
a) 42520
b) 52520
c) 40520
d) 45220
e) None of these
8.
8.I. In Figure (I) if the shaded portion has a degree measure of 60^{o}, what per cent of the un-shaded area is the shaded area ?
a) 20%
b) 25%
c) 33%
d) 17.5%
e) None of these
8.II. In Figure (II), what percentage of the rectangular area is shaded ?
a) 20%
b) 30%
c) 27.5%
d) 25%
e) None of these
8.III In case of the triangle in Figure (III), the following equation holds good :-
a) a = b + c
b) b^{2}= c^{2} – 2 ac
c) c^{2} =a^{2} + 2ab
d) a = √b^{2} + c^{2}
e) None of these
8.IV. In Figure (IV), the shaded area is approximately
a) 0.758 sq. units
b) 0.785 sq. units
c) 0.857 sq. units
d) 0.985 sq. units
e) None of these
8.V. In Figure (V), the ratio Un-shaded area /Shaded area is :
a) 12:7
b) 12:5:8
c) 13:7
d) 13:9
e) None of these
8. VI. In figure (VI) the ratio
Striped + doted area + shaded area is equal to
Plain area
a) 57.85
b) 58:91
c) 51:89
d) 59:81
e) None of these (it being given that ABCD is a quadrilateral, where BC is parallel to AD and BAD = 45^{o})
Answers with Explanation
1. (I) a) 9
The number of employees who get ‘ABOVE AVERAGE’ grade in HRD = 1/3 of the total number of candidates in HRD.
= 1/3 x 48 = 16 Now , total number of employees in the finance department
=twice the number of candidates in HRD department who have scored ‘ABOVE AVERAGE’ grade = 12 x 16 = 32
Total number of candidates who have obtained ‘Average’ grade
= 6 times the number of candidates of the marketing department who have obtained ‘Excellent grade
= 6 x 6 = 36
Now, fill the table with this data and arrive at other figures by finding the difference between totals and respective heads, on completion of which the table would look like this :
GRADES | Total | ||||
Class | Excellent | Very Good | Above Average | Average | |
Marketing | 6 | 19 | 32 | 0 | 57 |
HRD | 2 | 5 | 16 | 25 | 48 |
Finance | 5 | 7 | 9 | 11 | 32 |
Total | 13 | 31 | 57 | 36 | 137 |
1. (II) a) Marketing Department
1. (III) d) 18.25%
1. (IV) b) Rs.604000/-
Total number of employees = 137
Less number of employees = – 36
————-
101
Fee per employee =Rs. 4500
Therefore, for 101 employees = Rs. 454500
Discount of 7.5% on Rs.4500 is Rs.4500 is Rs.337.50
Therefore, fee payable after discount = 4500.00
– 337.50
————–
4162.50
Therefore, fee After Discount payable in respect of 36 employees= 4162.50 x 36
Rs. 149850.00
Therefore, total fee payable by Company ABC Limited = 454500 + 149850 = Rs.604350
= Rs.604000/- to the nearest thousand .
2. (I) b) 3150.9
3464 +3034+3210 + 3106+3200+2984+3058 = 22056 = 3150.9
7 7
2. II) c) 2659.6
2523 +2860 +2660+2770+2665 = 13478 = 2695.6
5 5
2.(III) a) 5.80 per cent
May 3210
April 3034
176
176 x 100 = 5.80 per cent
3034
2.(IV) b) Decrease of 3.55 per cent
July 3200 x 100 = 115.52 per cent
2770
August 2984 x 100 = 111.97 per cent
2665
Therefore, per cent decrease = 115.52
– 111.97
3.55 per cent
Decrease of 3.55 per cent
2. (V) d) 585
Exports, March to May = 3297 + 2523 + 2860 = 8680
Exports, June to August = 2660 + 2770+2665= 8095
Therefore, Difference = 8680-8095 =585
2.(VI) c) 2652
Let export for February be X.
Therefore, for March = X + 24.32 X i.e. X (1 + 24.32 )
100 100
Now , X (1 + 24.32 ) = 3297
100 X (1+24.32) = 3297
100 x 100
Therefore X ( 10000 + 2432 ) = 3297
10000
Therefore, X ( 12432 ) = 3297
10000
Therefore, X = (3297 x 10000)
12432
X = 2652.03
approx. = 2652
2(VII) b) -159
Trade Balance for September = 2899 – 3058 = –159
3. e) Figure (V) In the problem, it is given that an unbiased die is tossed 60 times. Since the outcomes are random, we calculate the probability of each outcome. For one toss : Probability of each outcome. For one toss : Probability of ‘1’ appearing on the die = 1/6. Similarly the probability of ‘2’, ‘3’, ‘4’, ‘5’, ‘6’ appearing on the die is also 1/6. Hence, all probabilities are equal for ‘one’ toss (ie. 1/6) Therefore, for ‘1’ toss – A number appears 1/6 times. For ’60’ tosses – 1/6 x 60 = 10 times (ie. each number appears 10 times). Therefore , for ’60’ tosses ‘1’, ‘2’, ‘3’, ‘4’, ‘5’, ‘6’ each appear ’10’ times. Therefore, Figure (V) is appropriate.
4. I. b) 4
Exports are more than export if the ratio import /export is more than 1. in the case of company P, the ratio is more than 1 in 2005, 2007 2008 and 2009.
4. II. a) 3
Exports are more than imports if the ratio import/export is less than 1. In the case of company Q, the ratio is less than 1 in 2002, 2003 and 2005.
4. III. c) 57.6 crore
Let I1 = import for 2003
I2 = import for 2004
E1 = export for 2003
E2 = export for 2004
Then, from the graph, we have I1/E12 = (0.8) and I2/E2 = 0.8
Therefore, I1 = (0.8) Ex and I2 = (0.8) Ex.
Therefore, (I1 + I2) = 0.8(E1+E2)
It is given than Ex+E2 = 72 crore
Therefore, I1+I2 = (0.8) x 72 crore = 57.6 crore
4. IV. c) 2003
The exports of company Q with relation to imports were maximum in that year in which the ratio import/Export was minimum
This was in the year 2003
The phrase with relation to imports is a key phrase in the question. Without this key phrase. It is not possible to determine the year in which the exports of Company Q were maximum because the absolute values are not given. For a clear understanding of the concept, observe the following analysis.
Let us assume that,
for the year 2002 : imports = 100 crore
Exports = 500 crore
For the year 2003 : Imports = 60 crore
Exports = 100 crore
For the year 2004 : Imports = 160 crore
Exports = 200 crore
for the year 2005 : Imports = 180 crore
Exports = 600 crore
Therefore, The Import/Export ratios for the above years are as follows :
2002 : 100/500= 0.2
2003 : 60/100 = 0.6
2004 : 160/200 = 0.8
2005 : 180/600 = 0.3
At the first instance, by looking at the ratios, we ratios, we find that in the year 2002, tge ratui us nubunyn (i.e. 0.2) and hence, conclude that exports would be maximum during that year, which is false, since the maximum exports look place in the year 2005 (600 crores). But if we take the key phrase with relation to imports into account, then, in the above example, we find that the exports were maximum in the year 2002 with relation to imports. Exports with relation to imports OR Exports as a percentage of imports, for the above years are shown below :-
2002
(Exports/Imports x 100)% = 500/100 x 100)% = 500%
2003
(Exports/Imports x 100)% = 100/60 x 100)% = 166.67%
2004
(Exports/Imports x 100)% = 200/160 x 100)% = 125%
2005
(Exports/Imports x 100)% = 600/180 x 100)% = 333.33%
Thus, from the above calculations, we see that the Exports were maximum with relation to imports in the year 2002.
4. V. c) 103.95 crore
In the year 2007, for company Q, the ratio import/export = 1.35
Therefore, import = (1.35) x export
= 1.35 x 77 crore
= 103.95 crore
4. VI. a) 86.4 crore
Let import of Company P in 2006 = I1
Let import of Company Q in 2002 = I2
Let export of company P in 2006 = E1
Let export of Company Q in 2002 = E2
Given E1 + E2 = 96 crore
Now, from the graph, we can see that
I1/E1 = 0.9 and I2/E2 = 0.9
Therefore I1= (0.9) x E1 and I2 = (0.9) x E2
Therefore I1 + I2 = 0.9 (E1 +E2) = 0.9 (96 crore) = 86.4 crore
5. I. c) 58.64
French – 48.3^{o}
Hindi – 54.8^{o}
English – 45.0^{o}
Social Studies – 63.0^{o}
211.1^{o}
———-
211.1^{o } x 100 = 58.64 per cent of the total marks obtained
360^{o}
5. II. b) 46
Science – 72.8 ^{o}
Percentage of total = 72.8^{o} x 100 = 20.22 per cent
360^{o}
Therefore, Actual Marks Scored = 20.22 per cent of 440
= 88.97 = 89(approx.)
Maths – 76.1^{o}
Percentage of total = 76.1^{o} x 100 = 21.14 per cent
360^{o}
Therefore, Actual Marks Scored = 440 x 21.14 per cent
= 93.01 = 93 (approx.)
French – 48.3^{o}
Percentage of total = 48.3^{o} x 100 = 13.42 per cent
360^{o}
Therefore, Actual Mark = 13.42 per cent of 440
= 59.05 = 59 (approx.)
Social Studies – 63^{o
}Percentage of total = 63^{o} x 100 = 17.5 per cent
360^{o}
Therefore, Actual Mark = 17.5 per cent of 440
= 77 (approx.)
Therefore ,
(I) Science + Maths = 89+93 = 182
(II) French + Social Studies = 59+77 = 136
(III) -(II) = 182-136 = 46 marks
Alternatively : The sum of degree measures of Science and Maths = 72.8^{o} + 76.1^{o } = 148^{o }
The sum of the degree measures of French and Social Studies = 48.3^{o} + 63.0^{o} = 111.3^{o}
Therefore, the difference between the sum of the degree measures of Science and Maths and French and Social Studies = 148.9^{o} – 111.3^{o} = 37.6^{o}
Since the central angle of a Pie-chart = 360^{o} and the total marks = 440, therefore 360^{o} represents 440 marks, 37.6^{o} represents x marks.
Therefore, x = 37.6 x 440 = 45.9 (approx.46 marks)
360
5. III. d) Science and Social studies
Hindi – 54.8^{o}
English – 45.0^{o}
—–
9.8^{o}
——-
Science 72.8^{o}
Social studies (-)63.0^{o}
———
9.8^{o}
———
5. IV. e) Hindi
Marks scored = 67
Total marks obtained = 440
Therefore, he has scored 67/440 x100 = 15.23 per cent marks
Therefore, in Pie Diagram, it represents
360^{o }x 15.23 % = 54.8^{o}, Which is Hindi
Alternative Method
440 marks 360^{o
}67 marks X^{o
}Therefore, x = 67 x 360 = 54.8^{o}
440
on scanning through the pie-chart for a sector having degree measure of 54.8^{o} , we find it as Hindi.
6. I. (b) 62.46
Total production (PU+PR) for 2007-08 is 8.53 + 14.19 = 22.72
Therefore, percentage = 14.19 x 100 = 62.46 per cent
22.72
6. II. (c) 2006-07
6. III. (d) 2004-05
6. IV. (b) 92.80
Private Sector 2007-08 14.19
2002-03 7.36
———–
6.83
———–
6.83 x 100 = 92.80 per cent
7.36
6. V. (a) 37.85
PU 8.54
PR 14.02
———–
22.56
———–
Therefore, per cent share of PU sector = 8.54 /22.56 x100 = 37.85 per cent
7.I. (e) None of these
7.II (c) 1998-99
Ratio of Import/Export
i) 1.419 ii) 1.396 iii) 1.279 iv) 1.327
v) 1.086 vi) 1.180 vii) 1.048 viii) 1.088
ix) 1.153 x) 1.164
Ratio was maximum for 1998-99
7.III (c) 36.82
Annual percentage increase in Exports
i) 1999-2000 20232
– 15674
———-
4558
———-
4558 x 100 = 29.08 %
15674 100
Similarly for 2000-01 it is 36.82 % 2001-02 it is 17.60%
2002-03 it is 35.29 % 2003-04 it is 21.90%
2004-05 it is 29.92% 2005-06 it is 18.53 %
2006-07 it is 28.64% 2007-08 it is 10.50%
Therefore maximum is 36.82%
7.IV (a) 10.78
For 1999-2000 28235
– 22244
———-
5991
———–
5991 x 100 = 26.93%
22244 100
Similarly for 2000-01 it is 25.43 % 2001-02 it is 21.96%
2002-03 it is 10.78 % 2003-04 it is 32.44%
2004-05 it is 15.35% 2005-06 it is 23.08%
2006-07 it is 36.35% 2007-08 it is 11.55%
Therefore minimum is 10.78 %
7.V (a) 42520
8.I (a) 20%
The Central Angle of the shaded area is 60 . Therefore, the area of the shaded region is 1/6th the area of the entire circle. (60^{o} /360^{o} = 1/6)
Therefore , unshaded area = 5/6th area of the entire circle . No, 1/6th is 20% of 5/6.
8.II (d) 25%
The rectangle in figure (II) can be divided into 8 triangles, all of them equal in area to the shaded triangle.
Therefore, the area occupied by the two shaded triangles is
= 1/8 + 1/8 = 2/8 = 1/4 the area of the entire rectangle
Therefore, the shaded area is 1/4 x 100 = 25% of the area of the rectangle
8.III (d) a = √b^{2} + c^{2 }(Angle in a semi-circle is a right-angle)
Therefore, triangle ABC is a right angled triangle, right-angled at A. Therefore, by Pythagoras Theorem, we have
a^{2} =b ^{2} +c^{2} or a = √b^{2} + c^{2 }
8.IV (c) 0.857 sq. units
Area of square = 2 x 2 = 4 sq. units
Area of circle = πr^{2 }= π x 1 x 1 = 22/7 sq. units
Area shaded = (Area of square) – (Area of circle) = 4-22/7 = 6/7 = 0.857 sq. units (approx.)
8.V (d) 13:9
Area of the bigger circle = πr^{2}_{1}, r_{1} = 1 unit
Therefore, area = π x 1 x1 = 22/7 sq. units
Area of smaller circle = πr^{2}_{2}, r_{2} = 1/2 units
Therefore, are = π x 1/2 x 1/2 = 22/7 x 1/4 = 11/14 sq. units (shaded)
Area of the triangle = 1/2 x Base x height
= 1/2 x 1 x 1
= 1/2 sq.units (shaded)
Therefore, total of shaded area = 11 + 1 = 11+7 = 18 = 9
14 2 14 14 7
Therefore, un-shaded area = (area of bigger circle) – (total shaded area)
= 22 – 9 = 13
7 7 7
Therefore, Ratio Un-shaded are = 13/7 = 13 x 7
9/7 7 9
= 13/9 OR 13:9
8.VI (d) 59:81