# GlobalEdge Aptitude Questions and Answers

**GlobalEdge Aptitude Questions and Answers**

1.If the number 481 * 673 is completely divisible by 9, then the smallest whole number in place of * will be:

A.2

B.5

C.6

D.7

E.None of these

Answer:D

Ex:Sum of digits = (4 + 8 + 1 + x + 6 + 7 + 3) = (29 + x), which must be divisible by 9.

Therefore, x = 7.

2.3897 x 999 = ?

A.3883203

B.3893103

C.3639403

D.3791203

E.None of these

Answer:B

Option : B

EX:3897 x 999 = 3897 x (1000 – 1)

= 3897 x 1000 – 3897 x 1

= 3897000 – 3897

= 3893103.

3.Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same

piece of work is:

A.15

B.16

C.18

D.25

Answer:B

Ex:Ratio of times taken by Sakshi and Tanya = 125:100 = 5:4.

Suppose Tanya takes x days to do the work.

5 : 4 :: 20 : x ⇒ x =(4 x 20)/5

⇒ x = 16 days

Hence, Tanya takes 16 days to complete the work.

4.A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In

how many days shall B finish the whole work alone?

A.30 days

B.40 days

C.60 days

D.70 days

Answer:C

Ex:Let A’s 1 day’s work = x and B’s 1 day’s work = y.

Then, x + y =1/30 and 16x + 44y = 1.

Solving these two equations, we get: x =1/60 and y =1/60

Hence, B alone shall finish the whole work in 60 days.

5.A train left station at A hour B minutes. It reached station Y at B hour C minutes on the same day, after travelling C hours A

minutes (clock shows time from 0 hours to 24 hours). Number of possible value of A is?

A.0

B.1

C.2

D.3

Answer:A

Ex:A hours + C ours = B hours …..(i)

A, C and B cannot have values greater than or equal to 24

B minutes + A minutes = C minutes …..(ii)

Looking at two equation, we get no value of A satisfies both equation.

6.An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 5/3 hours, it must travel

at a speed of:

A.300 kmph

B.360 kmph

C.600 kmph

D.720 kmph

Answer:D

Ex:Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed =1200/(5/3)km/hr

∴ Required speed = 1200 x (3/5)km/hr = 720 km/hr

7.A merchant marks his goods up by 75% above his cost price. What is the maximum % discount that he can offer so that he ends up

selling at no profit or loss?

A.75%

B.46.67%

C.300%

D.42.85%

Answer:D

Ex:Let us assume that the cost price of the article = Rs.100

Therefore, the merchant would have marked it to Rs.100 + 75% of Rs.100 = 100 + 75 = 175.

Now, if he sells it at no profit or loss, he sells it at the cost price.i.e. he offers a discount of Rs.75 on his selling price of

Rs.175

Therefore, his % discount = (75/175) x 100= 42.85%

8.The average weight of a class of 24 students is 36 years. When the weight of the teacher is also included, the average weight

increases by 1kg. What is the weight of the teacher?

A.60 kgs

B.61 kgs

C.37 kgs

D.None of these

Answer:B

Ex:The average weight of a class of 24 students = 36 kgs.

Therefore, the total weight of the class = 24 x 36 = 864 kgs

When the weight of the teacher is included, there are 25 individuals.

The average weight increases by 1kg. That is the new average weight = 37 kgs.

Therefore, the total weight of the 24 students plus the teacher = 25 x 37 = 925

Weight of the teacher = Weight of 24 students + teacher – weight of 24 students = 925 – 864 = 61 kgs

9.Ayesha’s father was 38 years of age when she was born while her mother was 36 years old when her brother four year younger to her

was born. What is the difference between the ages of her parents?

A.2 years

B.4 years

C.6 years

D.8 years

Answer:C

Ex:Mother’s age when ayesha’s brother was born = 36 years.

Father’s age when Ayesha’s brother was born = (38 + 4) = 42 years.

So, required difference = ( 42 – 36 ) years = 6 years.

10.Two number are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is:

A.27

B.33

C.49

D.55

Answer:B

Ex:Let the numbers be 3x and 5x.

Then, (3x – 9)/5x – 9=12/23

⇒ 23(3x – 9) = 12(5x – 9)

⇒ 9x = 99

⇒ x = 11.

∴ The smaller number = (3 x 11) = 33.

11.January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?

A.Monday

B.Tuesday

C.Wednesday

D.Sunday

Answer:C

Ex:The year 2007 is an ordinary year. So, it has 1 odd day.

1st day of the year 2007 was Monday.

1st day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.

12.If REASON is coded as 5 and BELIEVED is coded as 7, what will be coded for GOVERMENT?

A.6

B.8

C.9

D.10

Answer:C

EX:Code for the given word = (number of letter in the word) – 1.

So, the code for GOVERNMENT= 10 – 1 = 9.

13.If Z = 52 and ACT = 48, then BAT = ?

A.39

B.41

C.44

D.46

Answer:D

EX:In the given code, A = 2, B = 4, …. ,Z = 52.

So, ACT = 2 + 6 + 40 = 48 AND BAT = 4 + 2 + 40 = 46

14.My father’s only brother’s wife’s only daughter’s paternal uncle is my mother’s

A.father-in-law

B.husband

C.son

D.uncle

Answer:B

EX:My father’s only brother’s wife is my father’s sister-in-law.

My father’s sister-in-law’s only daughter is my father’s niece.

My father’s niece’s paternal uncle is my father. My father is my mother’s husband.

15.How is my father’s brother’s only sibling’s mother related to me?

A.Mother

B.Daughter

C.Aunt

D.Grandmother

Answer:D

EX:My father’s brother’s only sibling is my father.

My father’s mother is my grandmother.

16.21, 9, 21, 11, 21, 13, 21, …?

A.14

B.15

C.21

D.23

Answer:B

In the sequence alternate number is added by 2

17.53, 53, 40, 40, 27, 27, …?

A. 12

B. 14

C. 27

D. 53

Answer:B

In the sequence -13 is done after repeating a number

18.If even numbered dice have even number of dots on their top faces, then what would be the total number of dots on the top faces of

their dice?

A.12

B.14

C.18

D.24

Answer:C

Ex:Even numbered dice are: (II), (IV) and (VI)

No. of dots on the top face of (II) dice = 6

No. of dots on the top face of (IV) dice = 6

and No. of dots on the top face of (VI) dice = 6

Therefore Required total = 6 + 6 + 6 = 18

.Direction to solve(19-20):

In each question below is given a statement followed by two conclusions numbered I and II.

You have to assume everything in the statement to be true, then consider the two conclusions together and decide which of them

logically follows beyond a reasonable doubt from the information given in the statement.

Give answer:

(A) If only conclusion I follows.

(B) If only conclusion II follows

(C) If either I or II follows

(D) If neither I nor II follows and

(E) If both I and II follow.

19.Statements: Reading makes a full man, conference a ready man and writing an exact man.

Conclusions:I. Pointed and precise expression comes only through extensive writing.

II. Extensive reading makes a complete man.

A.Only conclusion I follows

B.Only conclusion II follows

C.Either I or II follows

D.Neither I nor II follows

E.Both I and II follow

Answer:E

Ex:Clearly, I follows from the fact that writing makes an exact man.

Conclusion II also directly follows from the statement.

20.Statements: Death keeps no calendar.

Conclusions:I. Man must die one day.

II. Death can come at any time.

A.Only conclusion I follows

B.Only conclusion II follows

C.Either I or II follows

D.Neither I nor II follows

E.Both I and II follow

Answer:E

EX:Both I and II directly follow from the statement.