Texas Instruments Placement-Paper

Texas Instruments  

 Interview Procedure

The test is followed by a Technical and a HR interview. The technical interview is highly specialized and covers almost all subjects you have done in your curriculum. Some puzzles may also be asked in the interview. Special emphasis is laid on C and Data Structures.

Written Test paper there was 20 questions as follows in 60 minutes second part consists of 36 queue. in 30 minutes all questions are diagramatical.(figurs)..

Texas

1. if a 5-stage pipe-line is flushed and then we have to execute 5 and 12 instructions respectively then no. of cycles will be
   a. 5 and 12
   b. 6 and 13
   c. 9 and 16
   d.none

2. k-map
   ab
   ———-
   c 1 x 0 0
   1 x 0 x
   solve it

   a. A.B
   B. ~A
   C. ~B
   D. A+B

3. CHAR A[10][15] AND INT B[10][15] IS DEFINED WHAT’S THE ADDRESS OF A[3][4] AND B[3][4] IF ADDRESS OD A IS OX1000 AND B IS 0X2000

   A. 0X1030 AND 0X20C3
   B. OX1031 AND OX20C4
   AND SOME OTHERS..

4. int f(int *a)
   {
   int b=5;
   a=&b;
   }

   main()
   {
   int i;
   printf(“\n %d”,i);
   f(&i);
   printf(“\n %d”,i);
   }

   what’s the output .

   1.10,5
   2,10,10
   c.5,5
   d. none

5. main()
   {
   int i;
   fork();
   fork();
   fork();
   printf(“—-“);
   }

   how many times the printf will be executed .
   a.3
   b. 6
   c.5
   d. 8

6. void f(int i)
   {
   int j;
   for (j=0;j<16;j++)
   {
   if (i & (0x8000>>j))
   printf(“1”);
   else
   printf(“0”);
   }
   }
   what’s the purpose of the program

   a. its output is hex representation of i
   b. bcd
   c. binary
   d. decimal

7. #define f(a,b) a+b
   #define g(a,b) a*b

   main()
   {

   int m;
   m=2*f(3,g(4,5));
   printf(“\n m is %d”,m);
   }

   what’s the value of m
   a.70
   b.50
   c.26
   d. 69

8. main()
   {
   char a[10];
   strcpy(a,””);
   if (a==NULL)
   printf(“\a is null”);
   else
   printf(“\n a is not null”);}

   what happens with it .
   a. compile time error.
   b. run-time error.
   c. a is null
   d. a is not null.

9. char a[5]=”hello”

   a. in array we can’t do the operation .
   b. size of a is too large
   c. size of a is too small
   d. nothing wrong with it .

10. local variables can be store by compiler
    a. in register or heap
    b. in register or stack
    c .in stack or heap .
    d. global memory.

11. average and worst time complexity in a sorted binary tree is

12. a tree is given and ask to find its meaning (parse-tree)
    (expression tree)
    ans. ((a+b)-(c*d)) ( not confirmed)

13. convert 40.xxxx into binary .

14. global variable conflicts due to multiple file occurance
    is resolved during
    a. compile-time
    b. run-time
    c. link-time
    d. load-time

15. two program is given of factorial. one with recursion and one without recursion .question was which program won’t run for very big no. input because
    of stack overfow .
    a. i only (ans.)
    b. ii only
    c. i& ii both .
    c. none

16. struct a
    {
    int a;
    char b;
    int c;
    }
    union b
    {
    char a;
    int b;
    int c;
    };
    which is correct .
    a. size of a is always diff. form size of b.(ans.)
    b. size of a is always same form size of b.
    c. we can’t say anything because of not-homogeneous (not in ordered)
    d. size of a can be same if …