111. | If (64)2 – (36)2 = 20 x x, then x = ? | |||||||||||||
Answer: Option D Explanation:
20 x x = (64 + 36)(64 – 36) = 100 x 28
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113. | (22 + 42 + 62 + … + 202) = ? | |||||||||||||||||||||
Answer: Option C Explanation:
(22 + 42 + 62 + … + 202) = (1 x 2)2 + (2 x 2)2 + (2 x 3)2 + … + (2 x 10)2 = (22 x 12) + (22 x 22) + (22 x 32) + … + (22 x 102) = 22 x [12 + 22 + 32 + … + 102]
= (4 x 5 x 77) = 1540. |
114. |
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Answer: Option B Explanation:
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116. | The sum of first 45 natural numbers is: | |||||||||||||||
Answer: Option A Explanation:
Let Sn = (1 + 2 + 3 + … + 45) This is an A.P. in which a = 1, d = 1, n = 45 and l = 45
Required sum = 1035. |
117. | 666 ÷ 6 ÷ 3 = ? | ||||||||||||||||
Answer: Option A Explanation:
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118. | The sum of all two digit numbers divisible by 5 is: | |||||||||||||||||
Answer: Option D Explanation:
Required numbers are 10, 15, 20, 25, …, 95 This is an A.P. in which a = 10, d = 5 and l = 95. tn = 95 a + (n – 1)d = 95 10 + (n – 1) x 5 = 95 (n – 1) x 5 = 85 (n – 1) = 17 n = 18
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119. | The difference between the place values of two sevens in the numeral 69758472 is | |||||||
Answer: Option C Explanation: Required difference = (700000 – 70) = 699930 |
120. | On dividing a number by 68, we get 269 as quotient and 0 as remainder. On dividing the same number by 67, what will the remainder ? | |||||||
Answer: Option B Explanation:
Number = 269 x 68 + 0 = 18292 67) 18292 (273 134 ---- 489 469 ---- 202 201 --- 1 --- Therefore, Required remainder = 1 |