Ratio and proportion aptitude questions

1. A and B together have Rs. 1210. If of A’s amount is equal to of B’s amount, how much amount does B have?
A. Rs. 460 B. Rs. 484
C. Rs. 550 D. Rs. 664

Answer: Option B

Explanation:

 

 

4 A = 2 B
15 5
A = 2 x 15 B
5 4

 

A = 3 B
2

 

A = 3
B 2

A : B = 3 : 2.

 

B’s share = Rs. 1210 x 2 = Rs. 484.
5

2. Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
A. 2 : 5 B. 3 : 5
C. 4 : 5 D. 6 : 7

Answer: Option C

Explanation:

 

Let the third number be x.

 

Then, first number = 120% of x = 120x = 6x
100 5

 

Second number = 150% of x = 150x = 3x
100 2

 

Ratio of first two numbers = 6x : 3x = 12x : 15x = 4 : 5.
5 2

3. A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B’s share?
A. Rs. 500 B. Rs. 1500
C. Rs. 2000 D. None of these

Answer: Option C

Explanation:

 

Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.

Then, 4x – 3x = 1000

x = 1000.

B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.


4. Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
A. 2 : 3 : 4 B. 6 : 7 : 8
C. 6 : 8 : 9 D. None of these

Answer: Option A

Explanation:

 

Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.

Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).

 

140 x 5x , 150 x 7x and 175 x 8x
100 100 100

 

7x, 21x and 14x.
2

 

The required ratio = 7x : 21x : 14x
2

14x : 21x : 28x

2 : 3 : 4.


5. In a mixture 60 litres, the ratio of milk and water 2 : 1. If the this ratio is to be 1 : 2, then the quanity of water to be further added is:
A. 20 litres B. 30 litres
C. 40 litres D. 60 litres

Answer: Option D

Explanation:

 

 

Quantity of milk = 60 x 2 litres = 40 litres.
3

Quantity of water in it = (60- 40) litres = 20 litres.

New ratio = 1 : 2

Let quantity of water to be added further be x litres.

Then, milk : water = 40 .
20 + x

 

Now, 40 = 1
20 + x 2

20 + x = 80

x = 60.

Quantity of water to be added = 60 litres.

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