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होम › भौतिकी › Kinematics - Equations of Motion

Kinematics - Equations of Motion — Physics Questions & Practice

1,180 Kinematics - Equations of Motion questions from Physics for competitive exams such as UPSC, Banking, SSC and Railway. Read the worked questions below, check every answer with an explanation, and track what you get wrong. का अभ्यास करें

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Kinematics - Equations of Motion पर अभ्यास प्रश्न — उत्तर सहित

Try each question first, then open the answer. Explanations are included.

1. An object starts with an initial velocity of 5 m/s and accelerates uniformly at 5 m/s^2 for 7 seconds. What distance does it cover? (s = ut + 1/2at^2)

  1. A155.5
  2. B162.5
  3. C130.081
  4. D157.5
उत्तर दिखाएँ

उत्तर: D

s = ut + (1/2)at^2 = (5 x 7) + (0.5 x 5 x 7^2) = 35 + 122.5 = 157.5 m.

2. An object starts with an initial velocity of 8 m/s and accelerates uniformly at 6 m/s^2 for 1 seconds. What is its final velocity? (v = u + at)

  1. A4
  2. B19
  3. C14
  4. D16
उत्तर दिखाएँ

उत्तर: C

v = u + at = 8 + (6 x 1) = 8 + 6 = 14 m/s.

3. An object starts with an initial velocity of 4 m/s and accelerates uniformly at 3 m/s^2 over a distance of 4 m. What is its final velocity? (v^2 = u^2 + 2as)

  1. A6.325
  2. B7.325
  3. C8.325
  4. D16.325
उत्तर दिखाएँ

उत्तर: A

v^2 = u^2 + 2as = 4^2 + (2 x 3 x 4) = 16 + 24 = 40. So v = sqrt(40) = 6.325 m/s.

4. An object starts with an initial velocity of 10 m/s and accelerates uniformly at 9 m/s^2 over a distance of 8 m. What is its final velocity? (v^2 = u^2 + 2as)

  1. A15.62
  2. B15.589
  3. C16.418
  4. D17.62
उत्तर दिखाएँ

उत्तर: A

v^2 = u^2 + 2as = 10^2 + (2 x 9 x 8) = 100 + 144 = 244. So v = sqrt(244) = 15.62 m/s.

5. An object starts with an initial velocity of 4 m/s and accelerates uniformly at 1 m/s^2 for 6 seconds. What is its final velocity? (v = u + at)

  1. A20
  2. B10.302
  3. C9
  4. D10
उत्तर दिखाएँ

उत्तर: D

v = u + at = 4 + (1 x 6) = 4 + 6 = 10 m/s.

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