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होम › भौतिकी › Simple Pendulum

Simple Pendulum — Physics Questions & Practice

12 Simple Pendulum questions from Physics for competitive exams such as UPSC, Banking, SSC and Railway. Read the worked questions below, check every answer with an explanation, and track what you get wrong. का अभ्यास करें

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Simple Pendulum पर अभ्यास प्रश्न — उत्तर सहित

Try each question first, then open the answer. Explanations are included.

1. A simple pendulum has a length of 0.5 m. What is its time period of oscillation? (T = 2*pi*sqrt(L/g), take g = 9.8 m/s^2)

  1. A1.419
  2. B3.419
  3. C1.282
  4. D0.419
उत्तर दिखाएँ

उत्तर: A

T = 2 x pi x sqrt(L/g) = 2 x 3.1416 x sqrt(0.5/9.8) = 1.419 seconds.

2. A simple pendulum has a length of 0.2 m. What is its time period of oscillation? (T = 2*pi*sqrt(L/g), take g = 9.8 m/s^2)

  1. A0.898
  2. B-0.102
  3. C-1.102
  4. D5.898
उत्तर दिखाएँ

उत्तर: A

T = 2 x pi x sqrt(L/g) = 2 x 3.1416 x sqrt(0.2/9.8) = 0.898 seconds.

3. A simple pendulum has a length of 2.5 m. What is its time period of oscillation? (T = 2*pi*sqrt(L/g), take g = 9.8 m/s^2)

  1. A8.173
  2. B3.173
  3. C2.173
  4. D13.173
उत्तर दिखाएँ

उत्तर: B

T = 2 x pi x sqrt(L/g) = 2 x 3.1416 x sqrt(2.5/9.8) = 3.173 seconds.

4. A simple pendulum has a length of 0.8 m. What is its time period of oscillation? (T = 2*pi*sqrt(L/g), take g = 9.8 m/s^2)

  1. A1.808
  2. B1.934
  3. C1.795
  4. D1.497
उत्तर दिखाएँ

उत्तर: C

T = 2 x pi x sqrt(L/g) = 2 x 3.1416 x sqrt(0.8/9.8) = 1.795 seconds.

5. A simple pendulum has a length of 0.6 m. What is its time period of oscillation? (T = 2*pi*sqrt(L/g), take g = 9.8 m/s^2)

  1. A1.524
  2. B2.555
  3. C1.555
  4. D11.555
उत्तर दिखाएँ

उत्तर: C

T = 2 x pi x sqrt(L/g) = 2 x 3.1416 x sqrt(0.6/9.8) = 1.555 seconds.

Simple Pendulum और प्रश्न हल करें

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