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Home › Physics › Simple Pendulum

Simple Pendulum — Physics Questions & Practice

Practise 12 Simple Pendulum questions from Physics for competitive exams such as UPSC, Banking, SSC and Railway. Read the worked questions below, check every answer with an explanation, and track what you get wrong.

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Practice questions on Simple Pendulum — with answers

Try each question first, then open the answer. Explanations are included.

1. A simple pendulum has a length of 0.5 m. What is its time period of oscillation? (T = 2*pi*sqrt(L/g), take g = 9.8 m/s^2)

  1. A1.419
  2. B3.419
  3. C1.282
  4. D0.419
Show answer

Answer: A

T = 2 x pi x sqrt(L/g) = 2 x 3.1416 x sqrt(0.5/9.8) = 1.419 seconds.

2. A simple pendulum has a length of 0.2 m. What is its time period of oscillation? (T = 2*pi*sqrt(L/g), take g = 9.8 m/s^2)

  1. A0.898
  2. B-0.102
  3. C-1.102
  4. D5.898
Show answer

Answer: A

T = 2 x pi x sqrt(L/g) = 2 x 3.1416 x sqrt(0.2/9.8) = 0.898 seconds.

3. A simple pendulum has a length of 2.5 m. What is its time period of oscillation? (T = 2*pi*sqrt(L/g), take g = 9.8 m/s^2)

  1. A8.173
  2. B3.173
  3. C2.173
  4. D13.173
Show answer

Answer: B

T = 2 x pi x sqrt(L/g) = 2 x 3.1416 x sqrt(2.5/9.8) = 3.173 seconds.

4. A simple pendulum has a length of 0.8 m. What is its time period of oscillation? (T = 2*pi*sqrt(L/g), take g = 9.8 m/s^2)

  1. A1.808
  2. B1.934
  3. C1.795
  4. D1.497
Show answer

Answer: C

T = 2 x pi x sqrt(L/g) = 2 x 3.1416 x sqrt(0.8/9.8) = 1.795 seconds.

5. A simple pendulum has a length of 0.6 m. What is its time period of oscillation? (T = 2*pi*sqrt(L/g), take g = 9.8 m/s^2)

  1. A1.524
  2. B2.555
  3. C1.555
  4. D11.555
Show answer

Answer: C

T = 2 x pi x sqrt(L/g) = 2 x 3.1416 x sqrt(0.6/9.8) = 1.555 seconds.

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