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Ages — Mathematics Questions & Practice

Practise 49 Ages questions from Mathematics for competitive exams such as UPSC, Banking, SSC and Railway. Read the worked questions below, check every answer with an explanation, and track what you get wrong.

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Practice questions on Ages — with answers

Try each question first, then open the answer. Explanations are included.

1. The ratio of the present ages of a father and son is 4:1. The father's age is 40 years. What is the son's age?

  1. A8 years
  2. B9 years
  3. C10 years
  4. D12 years
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Answer: C

Ratio 4:1 with father=40 means 1 part=10, so son's age=10 years.

2. A father is 30 years older than his son. In 5 years, the father will be twice as old as the son. What is the son's present age?

  1. A23 years
  2. B25 years
  3. C27 years
  4. D29 years
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Answer: B

Let son's age=x. Father=x+30. In 5 years: x+30+5=2(x+5) → x+35=2x+10 → x=25.

3. The sum of the ages of a father and son is 50 years. Five years ago, the father was 4 times as old as the son. What is the son's present age?

  1. A11 years
  2. B12 years
  3. C13 years
  4. D15 years
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Answer: C

Let son's present age=x, father=50-x. Five years ago: (50-x-5)=4(x-5) → 45-x=4x-20 → 65=5x → x=13.

4. A is twice as old as B. Five years ago, A was three times as old as B. What is B's present age?

  1. A8 years
  2. B9 years
  3. C10 years
  4. D12 years
Show answer

Answer: C

Let B's age=x, A=2x. Five years ago: 2x-5=3(x-5) → 2x-5=3x-15 → x=10.

5. The present age of a mother is 3 times that of her daughter. After 12 years, the mother's age will be twice that of her daughter. What is the daughter's present age?

  1. A10 years
  2. B12 years
  3. C14 years
  4. D16 years
Show answer

Answer: B

Let daughter's age=x, mother=3x. After 12 years: 3x+12=2(x+12) → 3x+12=2x+24 → x=12.

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