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Home › Physics › Circular Motion

Circular Motion — Physics Questions & Practice

Practise 851 Circular Motion questions from Physics for competitive exams such as UPSC, Banking, SSC and Railway. Read the worked questions below, check every answer with an explanation, and track what you get wrong.

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Practice questions on Circular Motion — with answers

Try each question first, then open the answer. Explanations are included.

1. An object of mass 3 kg moves in a circular path of radius 2 m at a speed of 5 m/s. What is the centripetal force acting on it? (F = mv^2/r)

  1. A37.5
  2. B32.5
  3. C28.296
  4. D45.609
Show answer

Answer: A

Centripetal force F = mv^2/r = (3 x 5^2)/2 = (3 x 25)/2 = 37.5 N.

2. An object of mass 2 kg moves in a circular path of radius 8 m at a speed of 18 m/s. What is the centripetal force acting on it? (F = mv^2/r)

  1. A84.629
  2. B96.607
  3. C81
  4. D85.186
Show answer

Answer: C

Centripetal force F = mv^2/r = (2 x 18^2)/8 = (2 x 324)/8 = 81 N.

3. An object moves in a circular path of radius 1 m at a speed of 23 m/s. What is its centripetal acceleration? (a = v^2/r)

  1. A519
  2. B634.256
  3. C529
  4. D518.572
Show answer

Answer: C

Centripetal acceleration a = v^2/r = 23^2/1 = 529/1 = 529 m/s^2.

4. An object of mass 4 kg moves in a circular path of radius 5 m at a speed of 5 m/s. What is the centripetal force acting on it? (F = mv^2/r)

  1. A24.896
  2. B15
  3. C18.631
  4. D20
Show answer

Answer: D

Centripetal force F = mv^2/r = (4 x 5^2)/5 = (4 x 25)/5 = 20 N.

5. An object of mass 3 kg moves in a circular path of radius 9 m at a speed of 11 m/s. What is the centripetal force acting on it? (F = mv^2/r)

  1. A40.333
  2. B39.531
  3. C33.603
  4. D46.844
Show answer

Answer: A

Centripetal force F = mv^2/r = (3 x 11^2)/9 = (3 x 121)/9 = 40.333 N.

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